SOLUTION: solve sin^2 x-sin x-2=0 for 0<= x < 360

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Question 217160: solve sin^2 x-sin x-2=0 for 0<= x < 360
Answer by chibisan(131) About Me  (Show Source):
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sin^2x-sinx-2=0
(sinx +1)(sinx -2) =0
sinx = -1
so the basic angle will be 90°
x = 180° + 90° , 360° - 90°
x = 270°
sinx = 2
(no solution)
thus , x = 270° is the only answer .