Question 216926: A mathematics class consist of 15 boys and 25 girls. A.In how many ways can the position of President, Vise-President, secretary, treasurer, and auditor be filled if no student may hold more than one position? B.In how many ways can 5 representatives be chosen from the class? C.If exactly 2 girls are chosen, in how many ways can the 5 representatives be chosen?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A mathematics class consist of 15 boys and 25 girls.
A.In how many ways can the position of President, Vise-President, secretary, treasurer, and auditor be filled if no student may hold more than one position?
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Ans: 50P5 = 50*49*48*47*46
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B.In how many ways can 5 representatives be chosen from the class?
Ans: 50C5 = 2118760
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C.If exactly 2 girls are chosen, in how many ways can the 5 representatives be chosen?
Ans: 25C2*15C3 = 300*455 = 136,500
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Cheers,
Stan H.
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