SOLUTION: There are three consecutive odd integers. The middle integer is 116 less than three times the smallest integer. What are the three integers?

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Question 216857: There are three consecutive odd integers. The middle integer is 116 less than three times the smallest integer. What are the three integers?
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
There are three consecutive odd integers. The middle integer is 116 less than three times the smallest integer. What are the three integers?

Step 1. Let n be the smallest odd integer.

Step 2. Let n+2 and n+4 be the next two odd and consecutive integers.

Step 3. Let 3n be three times the smallest integer

Step 4. Then n+2=3n+116 since middle integer is 116 less than three times the smallest integer

Step 5. Solving the equation in Step 4 yields the following steps

n%2B2=3n-116

Add 116-n to both sides of the equation

n%2B2%2B116-n=3n-116%2B116-n

118=2n

Divide 2 to both sides of the equation

118%2F2=2n%2F2

59=n

Then n%2B2=61 and n%2B4=63

Check middle integer....61=3*59-116=61...which is a true statement.

Step 6. ANSWER: The integers are 59, 61, and 63.

I hope the above steps were helpful.

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J