Step 2. Let n+2, n+4, and n+6 be the next three odd and consecutive integers.
Step 3. Then n+n+2+n+4+n+6=440 since four consecutive odd integers that have a sum of 440.
Step 4. Simplifying and olving the equation in Step 3 yields the following steps:
Subtract 12 from both sides of the equation yields
Divide 4 to both sides of the equation
Then
Check sum...107+109+111+113=440...which is a true statement.
Step 5. The 4 consecutive odd integers are: 107, 109, 111, and 113.
I hope the above steps were helpful.
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