SOLUTION: Can you please help me find four consecutive odd integers that have a sum of 440

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Question 216836: Can you please help me find four consecutive odd integers that have a sum of 440
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
Can you please help me find four consecutive odd integers that have a sum of 440.

Step 1. Let n be one odd integer.

Step 2. Let n+2, n+4, and n+6 be the next three odd and consecutive integers.

Step 3. Then n+n+2+n+4+n+6=440 since four consecutive odd integers that have a sum of 440.

Step 4. Simplifying and olving the equation in Step 3 yields the following steps:

n%2Bn%2B2%2Bn%2B4%2Bn%2B6=440

4n%2B12=440

Subtract 12 from both sides of the equation yields

4n%2B12-12=440-12

4n=428

Divide 4 to both sides of the equation

4n%2F4=428%2F4

n=107

Then n%2B2=109 n%2B4=111 n%2B6=113

Check sum...107+109+111+113=440...which is a true statement.

Step 5. The 4 consecutive odd integers are: 107, 109, 111, and 113.

I hope the above steps were helpful.

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J