SOLUTION: how do you graph: 6x-5y+20=0?

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Question 216710: how do you graph:
6x-5y+20=0?

Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
how do you graph:

6x-5y%2B20=0?

Step 1. A relatively easy way is pick two point and plot a line between the two points. Two points could be (0,b) and (a,0) where b is the y-intercept and a is the x-intercept.

Step 2. Let's start with (0,b) where x=0 and y=b. Substitute x=0 into

6x-5y%2B20 or in standard form as 6x-5y=20

6%2A0-5y=20

Divide by -5 to both sides of the equation

-5y%2F-5=20%2F-5

y=-4 or y=b=-4

So we have point (0,-4)

Step 3. Let's start with (a,0) where x=a and y=0. Substitute y=0 and solve for x=a.

6x-5y=20

6x-5%2A0=20

6x=20

Divide by 6 on both sides of the equation.

6x%2F6=20%2F6

x=20%2F6=10%2F3=a

Now we have another point (10/3,0).

Step 4. We now have two points to plot: (0,-4)and (10/3,0) found in Steps 2 and 3. Use these points to draw a line as shown below:

graph%28400%2C400%2C+-10%2C10%2C-10%2C10%2C+6x%2F5-4%29

I hope the above steps were helpful.

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J