SOLUTION: find three consecutive integers such that the sum of one-half of the smallest and one-third of the largest is one less than the other integer

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Question 216620: find three consecutive integers such that the sum of one-half of the smallest and one-third of the largest is one less than the other integer
Answer by RAY100(1637) About Me  (Show Source):
You can put this solution on YOUR website!
Let x,,,,x+1,,,,,x+2,,,,be consecutive integers
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(x/2) + { (x+2)/3} = (x+1) -1
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x/2 + x/3 +2/3 = x,,,,,mult by 6
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3x +2x +4 = 6x
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4=x,,,,,,,x+1=5,,,,,x+2=6
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checking
4/2 + 6/3 = 5-1
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2+2 =4,,,,,,ok
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