SOLUTION: how to resolve this 3(x-4)>15 28<4(5-2x) 3(2n+1)>4n+9 3n-10<7(2+n)

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Question 21647: how to resolve this
3(x-4)>15
28<4(5-2x)
3(2n+1)>4n+9
3n-10<7(2+n)
Answer by rahman(247) About Me  (Show Source):
You can put this solution on YOUR website!
3(x-4)>15 ------>Divide by 3
x-4>5
x-4+4>5+4
x>9
==================
28<4(5-2x)------->Divide by 4
7<5-2x
7-5<5-5-2x
2<-2x------------>Divide by -2, sign must changed
-1>x or x<-1
==================
3(2n+1)>4n+9
6n+3>4n+9
6n-4n>9-3
2n>6
n>3
===================
3n-10<7(2+n)
3n-10<14+7n
3n-7n<14+10
-4n<24 ------->Divide by -4
n>-7