SOLUTION: This is the problem I'm trying to get, please help me if you can. "The density of a square is known to be 4 g/mL. Its mass is 32 g. What is the length, cm, of the side of the squar

Algebra ->  Volume -> SOLUTION: This is the problem I'm trying to get, please help me if you can. "The density of a square is known to be 4 g/mL. Its mass is 32 g. What is the length, cm, of the side of the squar      Log On


   



Question 216119: This is the problem I'm trying to get, please help me if you can. "The density of a square is known to be 4 g/mL. Its mass is 32 g. What is the length, cm, of the side of the square? assume negligable thickness." I tried to take the mass and divide by four than use l8w8h but than I just realized that I only had a small part of the equation.
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
This is the problem I'm trying to get, please help me if you can. "The density of a square is known to be 4 g/mL. Its mass is 32 g. What is the length, cm, of the side of the square? assume negligable thickness." I tried to take the mass and divide by four than use l8w8h but than I just realized that I only had a small part of the equation.
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The volume is 8 ml (32/4).
8 = s^2*thickness
The length of the sides is sqrt(8/negligible).
Silly question, imo.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
"The density of a square is known to be 4 g/mL. Its mass is 32 g. What is the length, cm, of the side of the square? assume negligable thickness." I tried to take the mass and divide by four than use l8w8h but than I just realized that I only had a small part of the equation.
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If density is 4 g/mL then its 32 g/8mL
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You are not told the dimension associated with the mL
so we have to make an assumption.
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mL is a linear measure so the 8mL will have to be the
side of the square.
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Cheers,
Stan H.