SOLUTION: An old water pump can fill up a large trough in 10 minutes, but a second, newer pump takes only 3 minutes and 20 seconds to fill the trough. How long would it take to fill the trou

Algebra ->  Rate-of-work-word-problems -> SOLUTION: An old water pump can fill up a large trough in 10 minutes, but a second, newer pump takes only 3 minutes and 20 seconds to fill the trough. How long would it take to fill the trou      Log On


   



Question 215962This question is from textbook
: An old water pump can fill up a large trough in 10 minutes, but a second, newer pump takes only 3 minutes and 20 seconds to fill the trough. How long would it take to fill the trough using both pumps at the same time? This question is from textbook

Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
An old water pump can fill up a large trough in 10 minutes, but a second, newer pump takes only 3 minutes and 20 seconds to fill the trough. How long would it take to fill the trough using both pumps at the same time?
.
Convert rate to seconds:
Old pump:
fill trough per 10 minutes
is equivalent
fill trough per 600 seconds
.
New pump:
fill trough per 3 minutes 20 seconds
is equivalent
fill trough per 200 seconds
.
Let x = seconds it takes for both pump
then
x(1/600 + 1/200) = 1
Multiplying both sides by 600:
x(1 + 3) = 600
4x = 600
x = 150 seconds
.
So, for both pumps to fill the trough:
2 minutes 30 seconds