SOLUTION: for a recent job, a plumber earned 28 dollars per hour, and the plumber's apprentice earned 15 dollars per hour. The plumber worked 3 hours more than the apprentice. If together th

Algebra ->  Systems-of-equations -> SOLUTION: for a recent job, a plumber earned 28 dollars per hour, and the plumber's apprentice earned 15 dollars per hour. The plumber worked 3 hours more than the apprentice. If together th      Log On


   

Question 215878This question is from textbook algebra and trigonometry structure and method
: for a recent job, a plumber earned 28 dollars per hour, and the plumber's apprentice earned 15 dollars per hour. The plumber worked 3 hours more than the apprentice. If together they were paid 213 dollars, how much did they earn? This question is from textbook algebra and trigonometry structure and method

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
28(X+3)+15X=213
28X+84+15X=213
43X=213-84
43X=129
X=129/43
X=3 HOURS FOR THE APPRENTICE.
3+3=6 HOURS FOR THE PLUMBER.
PROOF:
28*6+15*3=213
168+45=213
213=213