Question 215788: three consecutive integers are such that three times the largest exceeds the sum of the two smaller integers by 47. find the integers Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! Let x, x+1 & x+2 be the three integers.
3(x+2)>x+x+1+47
3x+6>2x+48
3x-2x>48-6
x>42 ans.
Proof:
Let x=43
3(43+2)>42+42+1+47
3*45>132
135>132