SOLUTION: find three consecutive even integers so that the sum of the smallest interger and twice the second integer is 20 more than the third

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: find three consecutive even integers so that the sum of the smallest interger and twice the second integer is 20 more than the third      Log On


   



Question 215785This question is from textbook intermediate algebra with applications
: find three consecutive even integers so that the sum of the smallest interger and twice the second integer is 20 more than the third This question is from textbook intermediate algebra with applications

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
Let x, x+2 & x+4 be the 3 integers.
x+2(x+2)=(x+4)+20
x+2x+4=x+4+20
3x+4=x+24
3x-x=24-4
2x=20
x=20/1
x=10 ans. for the smallest integer.
10+2=12 for the middle integer.
10+4=14 ans. for the largest integer.
Proof:
10+2*12=14+20
10+24=34
34=34