SOLUTION: An auto averaged 40 mph for part of a trip and 50 mph for the remainder.
If the 5-hour trip covered 210 miles, for how long did the car average 40mph?
Question 215677: An auto averaged 40 mph for part of a trip and 50 mph for the remainder.
If the 5-hour trip covered 210 miles, for how long did the car average 40mph? Answer by drj(1380) (Show Source):
You can put this solution on YOUR website! An auto averaged 40 mph for part of a trip and 50 mph for the remainder.
If the 5-hour trip covered 210 miles, for how long did the car average 40mph?
Step 1. Let x be the length of time when traveling 40 mph.
Step 2. Let 5-x be the length of time traveling 50 mph.
Step 3. Let 40x be the distance traveled at 40 mph.
Step 4. Let 50(5-x) be the distance traveled at 50 mph.
Step 5. Then 40x+ 50(5-x)=210 as given by the problem statement.
Cartoon (animation) form: For tutors: simplify_cartoon( 40x+50*(5-x)=210 )
If you have a website, here's a link to this solution.
DETAILED EXPLANATION
Look at . Moved to the right of expression It becomes . Look at . Moved these terms to the left It becomes . Look at . Expanded term by using associative property on It becomes . Look at . Multiplied numerator integers It becomes . Look at . Added fractions or integers together It becomes . Look at . Eliminated similar terms, replacing them with It becomes . Look at . Added fractions or integers together It becomes . Look at . Removed extra sign in front of It becomes . Look at . Remove unneeded parentheses around factor It becomes . Look at . Solved linear equation equivalent to -10*x+40 =0 It becomes . Result: This is an equation! Solutions: x=4.
Universal Simplifier and Solver
Done!
With x=4, then 5-x=1.
Check distance...4*40+1*50=210...which is a true statement
Step 6. ANSWER. The car traveled for 4 hours at 40 mph.
I hope the above steps were helpful.
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