SOLUTION: The equation of the line that goes through the point ( 3 ,7 ) and is perpendicular to the line 3 x + 2 y = 4 can be written in the form y = mx+b where m is: and where b is:
So,
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-> SOLUTION: The equation of the line that goes through the point ( 3 ,7 ) and is perpendicular to the line 3 x + 2 y = 4 can be written in the form y = mx+b where m is: and where b is:
So,
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Question 215483: The equation of the line that goes through the point ( 3 ,7 ) and is perpendicular to the line 3 x + 2 y = 4 can be written in the form y = mx+b where m is: and where b is:
So, I got 3x + 2y = 4
2y = 4 - 3x
y = (4 - 3x)/2
so m=2/3
then i plugged everything and got
y - 7 = 2/3(x + 3)
y - 7 = 2/3x + 2
y = 2/3x + 2 + 7
y = 2/3x + 9
Somehow its wrong, can anyone help? Thank you! Found 2 solutions by Alan3354, Earlsdon:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! The equation of the line that goes through the point (3,7) and is perpendicular to the line 3 x + 2 y = 4 can be written in the form y = mx+b where m is: and where b is:
So, I got 3x + 2y = 4
2y = 4 - 3x
y = (4 - 3x)/2
************ y = (-3/2)x + 2
m = -3/2
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so m=2/3 ** That's the slope of lines perpendicular, the neg inverse of -3/2. Odd that you would have gotten the right answer using 2/3.
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then i plugged everything and got
y - 7 = 2/3(x + 3)
**************** y-7 = (2/3)(x - 3) You had (x+3)
y - 7 = 2/3x - 2
y = (2/3)x - 2 + 7
y = (2/3)x + 5
You can put this solution on YOUR website! Ok, you've got the slope of the new line correct. The negative reciprocal of the given line which has a slope: is, of course,
Now you can write: In order to find b, the y-intercept, substitute the x- and y-coordinates of the point (3, 7) through which this line passes. Simplify. so...
The final equation is:
(