SOLUTION: 10k-9=9k+10

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Question 215395: 10k-9=9k+10
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
10k-9=9k%2B10

Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


  • This is an equation! Solutions: k=19.
  • Graphical form: Equation 10k-9=9k%2B10 was fully solved.
  • Text form: 10k-9=9k+10 simplifies to 0=0
  • Cartoon (animation) form: simplify_cartoon%28+10k-9=9k%2B10+%29
    For tutors: simplify_cartoon( 10k-9=9k+10 )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at 10%2Ak-9=highlight_red%28+9%2Ak%2B10+%29.
Moved these terms to the left highlight_green%28+-9%2Ak+%29,highlight_green%28+-10+%29
It becomes 10%2Ak-9-highlight_green%28+9%2Ak+%29-highlight_green%28+10+%29=0.
Look at 10%2Ak-highlight_red%28+9+%29-9%2Ak-highlight_red%28+10+%29=0.
Added fractions or integers together
It becomes 10%2Ak%2Bhighlight_green%28+-19+%29-9%2Ak=0.
Look at 10%2Ak%2Bhighlight_red%28+-19+%29-9%2Ak=0.
Moved -19 to the right of expression
It becomes 10%2Ak-9%2Ak%2Bhighlight_green%28+-19+%29=0.
Look at 10%2Ak-9%2Ak%2Bhighlight_red%28+-19+%29=0.
Removed extra sign in front of -19
It becomes 10%2Ak-9%2Ak-highlight_green%28+19+%29=0.
Look at highlight_red%28+10%2Ak+%29-highlight_red%28+9%2Ak+%29-19=0.
Eliminated similar terms highlight_red%28+10%2Ak+%29,highlight_red%28+-9%2Ak+%29 replacing them with highlight_green%28+%2810-9%29%2Ak+%29
It becomes highlight_green%28+%2810-9%29%2Ak+%29-19=0.
Look at highlight_red%28+%2810-9%29+%29%2Ak-19=0.
Remove extraneous '1' from product highlight_red%28+%2810-9%29+%29
It becomes k-19=0.
Look at highlight_red%28+k-19+%29=0.
Solved linear equation highlight_red%28+k-19=0+%29 equivalent to k-19 =0
It becomes highlight_green%28+0+%29=0.
Result: 0=0
This is an equation! Solutions: k=19.

Universal Simplifier and Solver


Done!



I hope the above steps and explanation were helpful.

For Step-By-Step videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonmetry please visit http://www.FreedomUniversity.TV/courses/Trignometry.

Also, good luck in your studies and contact me at john@e-liteworks.com for your future math needs.

Respectfully,
Dr J