Question 215390: A man has 25 coins, all dimes and quarters. If he has $4.60 total, how many of each type of coin does he have? (Solve using a linear equation. No credit for guessing).
Answer by drj(1380)   (Show Source):
You can put this solution on YOUR website! A man has 25 coins, all dimes and quarters. If he has $4.60 total, how many of each type of coin does he have? (Solve using a linear equation. No credit for guessing).
Step 1. Let x be the number of dimes and let 25-x be the number of quarters.
Step 2. Let 0.10x be the total cost for x number of dimes
Step 3. Let 0.25(25-x) be the total cost for 25-x number of quarters.
Step 4. Since the man has $4.60, then 4.60=0.10x+0.25(25-x). Solving for x yields the following steps.
With x=11 , then 25-x=14. Check total: 11*0.10+14*0.25=4.60 which is a true statement.
Step 5. ANSWER: The number of dimes is 11 and the number of quarters is 14.
I hope the above steps and explanation were helpful.
For Step-By-Step videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonmetry please visit http://www.FreedomUniversity.TV/courses/Trignometry.
Also, good luck in your studies and contact me at john@e-liteworks.com for your future math needs.
Respectfully,
Dr J
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