SOLUTION: I have two 10 paisa coins. If 4/5 of what I have is 8/9 of what you have, how much do I have then?

Click here to see ALL problems on Probability-and-statistics

Question 215234This question is from textbook
: I have two 10 paisa coins. If 4/5 of what I have is 8/9 of what you have, how much do I have then?
This question is from textbook

Found 2 solutions by stanbon, krishna111:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
I have two 10 paisa coins. If 4/5 of what I have is 8/9 of what you have, how much do I have then?
-----------------------------
Equations:
(4/5)10 = (8/9)(you have)
(you have) = [(4/5)10](9/8)
you have = (2*9)/2 = 9 paisa coins
==================================
Cheers,
Stan H.

Answer by krishna111(1) (Show Source):
You can put this solution on YOUR website!
actually, i have two 10 paisa coins....
like that 20 paisa coins... (2*10)
you have = x
(4/5)*20 = (8/9)*x
lets 4/5*20=16....( 4*1/5*20=16 )
16 = 8/9 * x
x = 16 * (9/8)
x = 2 * 9
x = 18.