| 
 
 
 
Question 215168:  Please help!!!  Thank you!!
 
A line passes through the point (x,y) =(-2,-3) and has a slope of -4 . Write an equation for this line. 
 Found 2 solutions by  stanbon, drj: Answer by stanbon(75887)      (Show Source): 
You can  put this solution on YOUR website! A line passes through the point (x,y) =(-2,-3) and has a slope of -4 . Write an equation for this line. 
----------------------- 
Form is y = mx +b ; solve for "b": 
-3 = -4*-2 + b 
-3 = 8 + b 
b = -11 
-------------- 
Equation: 
y = -4x - 11 
======================= 
Cheers, 
Stan H. 
 Answer by drj(1380)      (Show Source): 
You can  put this solution on YOUR website! A line passes through the point (x,y) =(-2,-3) and has a slope of -4 . Write an equation for this line.
 
 
Step 1.  The slope m is given as
 
 
 
 
 
Step 2.  Let (x1,y1)=(-2,-3) or x1=2 and y1=1 .  Let other point be ((x2,y2)=(x,y) or x2=x and y2=y.
 
 
Step 3.  Now we're given  .  Substituting above values and variables in the slope equation m yields the following steps:
 
 
 
 
 
 
 
 
 
 
 
Step 4.  Multiply x+2 to both sides to get rid of denominator on right side of equation.
 
 
  
 
 
  
 
 
Step 5.  Now subtract 3 to both sides of equation to solve for y.
 
 
 
 
 
 
 
 
Step 6.  ANSWER.  y=-4x-11
 
 
Note:  the above equation can be rewritten as 
 
 
 
And the graph is shown below which is consistent with the above steps.
 
 
 | Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc |  
Equation   describes a sloping line. For any  
  equation ax+by+c = 0, slope is  .- X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x =  c/a. -11/4 = -2.75.
 - Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is -11/1 = -11.
 - Slope is -4/1 = -4.
 -  Equation in slope-intercept form: y=-4*x+-11.
 
  
 |  
  
 
 
 
I hope the above steps were helpful.  Good luck in your studies!
 
 
Respectfully, 
Dr J
 
 
For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra.
 
 
  | 
 
  
 
 |   
 
 |   
 |  |