Question 215166: If 3 times the smaller of two consecutive integers is added to 4 times the larger, the result is 102, Find the larger integer. Answer by drj(1380) (Show Source):
You can put this solution on YOUR website! If 3 times the smaller of two consecutive integers is added to 4 times the larger, the result is 102, Find the larger integer.
Step 1. Let n be one integer and let n+1 be the next consecutive integer.
Step 2. Let 4(n+1) is 4 times the larger integer
Step 3. Let 3n is 3 times the smaller integer
Step 4. 3n+4(n+1)=102 3 times the smaller of two consecutive integers is added to 4 times the larger, the result is 102
Step 5. The following steps will solve the equation in Step 4.
Cartoon (animation) form: For tutors: simplify_cartoon( 3n+4*(n+1)=102 )
If you have a website, here's a link to this solution.
DETAILED EXPLANATION
Look at . Moved these terms to the left It becomes . Look at . Expanded term by using associative property on It becomes . Look at . Multiplied numerator integers It becomes . Look at . Added fractions or integers together It becomes . Look at . Removed extra sign in front of It becomes . Look at . Eliminated similar terms, replacing them with It becomes . Look at . Added fractions or integers together It becomes . Look at . Remove unneeded parentheses around factor It becomes . Look at . Solved linear equation equivalent to 7*n-98 =0 It becomes . Result: This is an equation! Solutions: n=14.
Universal Simplifier and Solver
Done!
With n=14 , then n+1=15
Check 3*14+4*15=102 or 102=102 which is a true statement
Step 6. The integers are 14 and 15 where 15 is the larger integer.
I hope the above steps were helpful.
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