SOLUTION: the lenghth of one leg of a triangle is 9 ft.the length of the hypot. is 3 ft longer than the other leg.find the lenght of the hypto.n and the other leg.

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Question 215014: the lenghth of one leg of a triangle is 9 ft.the length of the hypot. is 3 ft longer than the other leg.find the lenght of the hypto.n and the other leg.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
Assuming this is a right triangle:
x^2+9^2=(x+3)^2
x^2+81=x^2+6x+9
x^2-x^2-6x=9-81
-6x=-72
x=-72/-6
x=12 ans. for the other leg
12+3=15 ans. for the hypotenuse.
Proof:
12^2+9^2=15^2
144+81= 225
225=225