SOLUTION: I need help with sloving quadractic equations by factoring: {{{-2x^2+13x+7=0}}}

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Question 214986: I need help with sloving quadractic equations by factoring:
-2x%5E2%2B13x%2B7=0

Found 2 solutions by jim_thompson5910, drj:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
First, we need to factor -2x%5E2%2B13x%2B7


-2x%5E2%2B13x%2B7 Start with the given expression.


-%282x%5E2-13x-7%29 Factor out the GCF -1.


Now let's try to factor the inner expression 2x%5E2-13x-7


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Looking at the expression 2x%5E2-13x-7, we can see that the first coefficient is 2, the second coefficient is -13, and the last term is -7.


Now multiply the first coefficient 2 by the last term -7 to get %282%29%28-7%29=-14.


Now the question is: what two whole numbers multiply to -14 (the previous product) and add to the second coefficient -13?


To find these two numbers, we need to list all of the factors of -14 (the previous product).


Factors of -14:
1,2,7,14
-1,-2,-7,-14


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to -14.
1*(-14) = -14
2*(-7) = -14
(-1)*(14) = -14
(-2)*(7) = -14

Now let's add up each pair of factors to see if one pair adds to the middle coefficient -13:


First NumberSecond NumberSum
1-141+(-14)=-13
2-72+(-7)=-5
-114-1+14=13
-27-2+7=5



From the table, we can see that the two numbers 1 and -14 add to -13 (the middle coefficient).


So the two numbers 1 and -14 both multiply to -14 and add to -13


Now replace the middle term -13x with x-14x. Remember, 1 and -14 add to -13. So this shows us that x-14x=-13x.


2x%5E2%2Bhighlight%28x-14x%29-7 Replace the second term -13x with x-14x.


%282x%5E2%2Bx%29%2B%28-14x-7%29 Group the terms into two pairs.


x%282x%2B1%29%2B%28-14x-7%29 Factor out the GCF x from the first group.


x%282x%2B1%29-7%282x%2B1%29 Factor out 7 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28x-7%29%282x%2B1%29 Combine like terms. Or factor out the common term 2x%2B1


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So -1%282x%5E2-13x-7%29 then factors further to -%28x-7%29%282x%2B1%29




So -2x%5E2%2B13x%2B7 completely factors to -%28x-7%29%282x%2B1%29.


In other words, -2x%5E2%2B13x%2B7=-%28x-7%29%282x%2B1%29.


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Now let's use the factorization above to solve -2x%5E2%2B13x%2B7=0


-2x%5E2%2B13x%2B7=0 Start with the given equation


-%28x-7%29%282x%2B1%29=0 Factor the left side (see above)



Now set each factor equal to zero:
x-7=0 or 2x%2B1=0


x=7 or x=-1%2F2 Now solve for x in each case



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Answer:


So the solutions are x=7 or x=-1%2F2

Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
I need help with sloving quadractic equations by factoring:


-2x%5E2%2B13x%2B7=0

Step 1. Multiply by -1 to get rid of negative in x-squared term.

2x%5E2-13x-7=0

Step 2. We need two integers m an n such that their products is n*m=-2*7=-14 and their sum n+m= -13.

After several tries, these numbers are -14 and 1.

Step 3. Express -13x as -13x=-14x+1x=-14x+x and replace this in Step 1.

2x%5E2-13x-7=%282x%5E2-14x%29%2B%28x-7%29

Step 4. Factor out 2x in the first group with parenthesis

2x%5E2-13x-7=2x%28x-7%29%2B1%28x-7%29

Step 5. Factor out x-7 common to the groups with parenthesis

2x%5E2-13x-7=%28x-7%29%282x%2B1%29=0

Step 6. The above equation yields two solutions as follows:

x-7=0 and 2x%2B1=0

x=7 and x=-1%2F2

As a check, let's use the quadratic formula given below and solve

Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 2x%5E2%2B-13x%2B-7+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-13%29%5E2-4%2A2%2A-7=225.

Discriminant d=225 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--13%2B-sqrt%28+225+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-13%29%2Bsqrt%28+225+%29%29%2F2%5C2+=+7
x%5B2%5D+=+%28-%28-13%29-sqrt%28+225+%29%29%2F2%5C2+=+-0.5

Quadratic expression 2x%5E2%2B-13x%2B-7 can be factored:
2x%5E2%2B-13x%2B-7+=+2%28x-7%29%2A%28x--0.5%29
Again, the answer is: 7, -0.5. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B-13%2Ax%2B-7+%29



Same result as before.

Step 7. ANSWER. The solutions are x=7 and x=-1%2F2

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Good luck in your studies!

Respectfully,
Dr J