SOLUTION: Two cyclists start biking from a trail 3 hours apart. The 2nd cyclist traveled at 10 miles per hour and starts 3 hours after the 1st cyclist who is traveling at 6 miles per hour. H
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Question 214967: Two cyclists start biking from a trail 3 hours apart. The 2nd cyclist traveled at 10 miles per hour and starts 3 hours after the 1st cyclist who is traveling at 6 miles per hour. How much time will pass before the 2nd cyclist catches up with the 1st cyclist from the time the 2nd cyclist started? Answer by drj(1380) (Show Source):
You can put this solution on YOUR website! Two cyclists start biking from a trail 3 hours apart. The 2nd cyclist traveled at 10 miles per hour and starts 3 hours after the 1st cyclist who is traveling at 6 miles per hour. How much time will pass before the 2nd cyclist catches up with the 1st cyclist from the time the 2nd cyclist started?
Step 1. Let x be the time 2nd cyclist catches up with the 1st cyclist.
Step 2. Let 6x+18 total distance traveled by first cyclist and where 3 hours * 6 mph =18 miles travels after three hours plus 6x miles.
Step 3. Let 10x distance traveled by 2nd cyclist.
Step 4. Set expression in Steps 2 and 3 to be equal since they will have traveled the same distance.
Step 5. It will take 4.5 hours to for the second cyclist to catch up with the first cyclist.
I hope the above steps were helpful.
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