Question 214906: a. the point in the axis that is equidistant from 12,6 and 8,2
b. the distance between the points 6,4 and 18,4
c. the distance between the points 1,4 and 19,6
d. the midpoint between 12,6 and 18,4
e. the midpoint between -6, 8 and 23, 5
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! a. the point in the axis that is equidistant from 12,6 and 8,2
What does "in the axis" mean?
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b. the distance between the points 6,4 and 18,4
s^2 = diffy^2 + diffx^2
s^2 = 0 + (18-6)^2
s^2 = 12^2
s = 12
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c. the distance between the points 1,4 and 19,6
Do it like b above.
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d. the midpoint between 12,6 and 18,4
Find the average of x and y separately
x: (12+18)/2 = 15
y: (6+4)/2 = 5
Midpoint = (15,5)
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e. the midpoint between -6, 8 and 23, 5
Same as d above.
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