Question 214848This question is from textbook Geometry for Enjoyment and Challenge
: i'm having trouble finding m<1 . . .
Given:
<1 and <2 are supplementary
<2 and <3 are supplementary
<1= x^2+3y
<2= 20y+3
<3= 3y+4x
Find: m<1
(does not require proof)
i've found x= -5.75+44.25, but i am confused on how to proceed ? how would you solve (-5.75+44.25)^2+3y+20y+3=180 ?
please help, thank you !! This question is from textbook Geometry for Enjoyment and Challenge
You can put this solution on YOUR website! Using the fact that the sum of supplementary angles is 180 degrees, we can write two equations in x and y: Substitute: we get:
1). Similarly for angles 2 and 3. Add the angles.
2). Simplifying 1). and 2). we have:
1a).
2a). Subtracting 2a) from 1a) we get:
3). Factor an x.
3a). so that: or Substitute x = 0 into equation 1a) and solve for y. or substitute x = 4 into equation 1a) and solve for y. Subtract 19 from both sides. Divide both sides by 23.
So angle 1 can have one of two measures: Substitute x = 0 and y = 7.6957 degrees. degrees.
or... x=4 and y = 7. degrees. degrees.
As you can see, in both cases, the sums of angle 1 and angle 2 are 180 degrees.
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