SOLUTION: Could you please help me with this problem Solve for x: {{{4x^4+20x^2=-25}}}

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Question 21482: Could you please help me with this problem
Solve for x: 4x%5E4%2B20x%5E2=-25

Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
4x^4+20x^2=-25
4x^4+20x^2+25=0
(2x^2)^2+2*(2X^2)(5)+(5)^2=0............
USE THE FORMULA (A+B)^2=A^2+B^2+2AB..WE GET
(2X^2+5)^2=0
HENCE 2X^2+5=0
X=+SQ.RT.(-5/2)=+i*SQ.RT.(5/2)....OR....
X=-SQ.RT.(-5/2)=-i*SQ.RT.(5/2)....OR....