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Question 214726: What are the four consecutive even integers that equal 308?
Found 2 solutions by stanbon, drj: Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! What are the four consecutive even integers that equal 308?
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1st 2x-2
2nd 2x
3rd 2x+2
4th 2x+4
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Add to get:
8x +4 = 308
8x = 304
x = 38
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2nd: 2x = 76
1st: 74
3rd: 78
4th: 80
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Cheers,
Stan H.
Answer by drj(1380) (Show Source):
You can put this solution on YOUR website! What are the four consecutive even integers that equal 308?
Step 1. Let n be an even integer, n+2, n+4, and n+6 be the next three consecutive integers.
Step 2. Then n+n+2+n+4+n+6=308 as given by the problem statement where the sum of the four consecutive integers equal to 308.
Step 3. The following steps will solve the equation in Step 2:
Solved by pluggable solver: EXPLAIN simplification of an expression |
Your Result:
YOUR ANSWER
- This is an equation! Solutions: n=74.
- Graphical form: Equation
was fully solved. - Text form: n+n+2+n+4+n+6=308 simplifies to 0=0
- Cartoon (animation) form:
For tutors: simplify_cartoon( n+n+2+n+4+n+6=308 )
- If you have a website, here's a link to this solution.
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DETAILED EXPLANATION
Look at . Added fractions or integers together It becomes .
Look at . Moved to the right of expression It becomes .
Look at . Eliminated similar terms , , , replacing them with  It becomes .
Look at . Added fractions or integers together It becomes .
Look at . Remove unneeded parentheses around factor  It becomes .
Look at . Moved these terms to the left  It becomes .
Look at . Added fractions or integers together It becomes .
Look at . Removed extra sign in front of  It becomes .
Look at . Solved linear equation equivalent to 4*n-296 =0 It becomes . Result: 
This is an equation! Solutions: n=74.
Universal Simplifier and Solver
Done!
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Step 4. The integers are: 74, 76, 78, and 80.
I hope the above steps were helpful.
For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
And good luck in your studies!
Respectfully,
Dr J
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