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Question 214334:  Does anyone know how to go about this problem? The difference of two positive numbers is 3 and the sum of their squares is 65. Find the numbers.  
 Answer by drj(1380)      (Show Source): 
You can  put this solution on YOUR website! Does anyone know how to go about this problem? The difference of two positive numbers is 3 and the sum of their squares is 65. Find the numbers. 
 
 
Step 1.  Let y be one positive and the larger number and x be the other positive and smaller number.
 
 
Step 2.  The problem statement provides the following relationships or equations:
 
 
  or    (A)
 
 
    (B)
 
 
Step 3.  Substitute (A) into (B)
 
 
 
 
 
 
 
 
Step 4.  Subtract 65 from both sides of equation.
 
 
 
 
 
 
 
 
 
 
 
Step 5.  We can use the quadratic formula given as   
 
 
where a=1, b=3, and c=-28
 
 
 | Solved by pluggable solver: SOLVE quadratic equation with variable |  
Quadratic equation   (in our case  ) has the following solutons: 
   
    
   
  For these solutions to exist, the discriminant   should not be a negative number. 
   
  First, we need to compute the discriminant  :  . 
   
  Discriminant d=121 is greater than zero. That means that there are two solutions:  . 
   
      
      
     
    Quadratic expression   can be factored: 
    
  Again, the answer is: 4, -7.
Here's your graph: 
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Step 6.  Based on the above steps, select 4 since we want a positive number.
 
 
With x=4, then y=3+4=7.
 
 
Check if  
 
 
 
 
 
 
 
 
  which is a true statement.
 
 
Step 7.  ANSWER:  The numbers are 4 and 7.
 
 
I hope the above steps were helpful. 
 
 
For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
 
 
And good luck in your studies!
 
 
Respectfully, 
Dr J
 
 
 
 
 
 
 
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