Question 214320: Please respod ASAP!!!!! THANKS!!
Find four consecutive even integers such that twice the least increased by the greatest is 96.
THANK YOU FOR ANY HELP!! All i really could use is the initial set up problem, then i can figure it out from there.
Thanks you!!!!!!!!
Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find four consecutive even integers such that twice the least increased by the greatest is 96.
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1st: 2x-2
2nd: 2x
3rd: 2x+2
4th: 2x+4
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Equation:
2(2x-2)+ (2x+4) = 96
4x-4 + 2x+4 = 96
6x = 96
x = 16
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1st: 30
2nd: 32
3rd: 34
4th: 36
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Cheers,
Stan H.
Answer by MathTherapy(10557)  (Show Source):
You can put this solution on YOUR website! Find four consecutive even integers such that twice the least increased by the greatest is 96.
Let the smallest number be S.
Because we're looking for CONSECUTIVE EVEN NUMBERS, the second smallest number would then be S + 2, the 3rd smallest S + 4, and the largest S + 6
Since we're told that twice the smallest increased, or added to the the largest is 96, then we'll have:
2S + S + 6 = 96
3S + 6 = 96
3S = 90
Therefore, the smallest number is 30, while the others are 32, 34, and 36, as we add 2 to each number to get the next consecutive EVEN INTEGER.
I probably went too far as you stated that you only need the problem to be set up, but, "what the heck!!"
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