SOLUTION: Jessica found $52.25 in the parking lot. There was 3 times as many $1 bills as $5 bills, one-half as many quarters as $1 bills, and two more dimes than $1 bills. How many $5 bills
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Question 214299: Jessica found $52.25 in the parking lot. There was 3 times as many $1 bills as $5 bills, one-half as many quarters as $1 bills, and two more dimes than $1 bills. How many $5 bills did Jessica find?
You can put this solution on YOUR website! Jessica found $52.25 in the parking lot.
There was 3 times as many $1 bills as $5 bills,
one-half as many quarters as $1 bills,
and two more dimes than $1 bills.
How many $5 bills did Jessica find?
:
Let c = no. of $1 bills
Let f = no. of $5 bills
Let d = no. of dimes
Let q = no. of quarters
;
Write an equation for each statement:
:
Jessica found $52.25 in the parking lot.
1c + 5f + .10d + .25q = 52.25
;
There was 3 times as many $1 bills as $5 bills,
c = 3f
or
f = c
:
one-half as many quarters as $1 bills,
q = .5c
:
two more dimes than $1 bills.
d = c + 2
:
Using the equation: 1c + 5f + .10d + .25q = 52.25
Substitute for f, d, and q, find c
1c + 5(c) + .10(c+2) + .25(.5c) = 52.25
:
1c + c + .1c + .2 + .125c = 52.25
;
1.225c + c = 52.25 - .2
:
1.225c + c = 52.05
:
Get rid of the denominator, multiply equation by 3, results:
3(1.225)c + 5c = 3(52.05)
:
3.675c + 5c = 156.15
:
8.675c = 156.15
c =
c = 18 ea $1 bills
:
How many $5 bills did Jessica find?
f = c
f = * 18
f = 6 ea $5 bills
:
:
Ill let you check the solution in the original equation with substitution
