SOLUTION: how do i solve {{{ 4 over x-2 + x over 2-x }}} ?

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Question 214258: how do i solve +4+over+x-2++%2B++x+over+2-x+ ?
Found 2 solutions by drj, checkley77:
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
How do i solve +4+over+x-2++%2B++x+over+%282-x%29+ ?

or writing above as

4%2F%28x-2%29%2Bx%2F%282-x%29

Simplify as follows and combine when the terms have a common denominator:



I hope the above steps were helpful.

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J


Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
4/(x-2)+x/(2-x)
4(2-X)+X(X-2)/(X-2)(2-X)
(8-4X+X^2-2X)/(X-2)(2-X)
(X^2-6X+8)/(X-2)(2-X)
(X-2)(X-4)/(X-2)(2-X) CANCEL OUT THE (X-2) TERMS.
(X-4)/(2-X) ANS.