SOLUTION: Find the real solution(s) of the equation involving rational exponents (x^2+6)^(2/3)=9

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Question 214168: Find the real solution(s) of the equation involving rational exponents
(x^2+6)^(2/3)=9
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
Find the real solution(s) of the equation involving rational exponents

%28x%5E2%2B6%29%5E%282%2F3%29=9

Step 1. Raise both sides of the equation by the power 3/2

%28%28x%5E2%2B6%29%5E%282%2F3%29%29%5E%283%2F2%29=9%5E%283%2F2%29 where 1/2 in the exponent is the square root and for this example sqrt%289%29=3

x%5E2%2B6=3%5E3=27

Step 2. Subtract 6 from both sides of the equation

x%5E2%2B6-6=27-6

x%5E2=21

x=sqrt%2821%29 or x=-sqrt%2821%29 ANSWER

I hope the above steps were helpful.

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J