SOLUTION: Could someone help me out with these two;
Give the logarithms of the following;
log(base 10)3.20
log(base10)second root (its like the the cube root just a 2 on place of the 3) 6
Algebra ->
Logarithm Solvers, Trainers and Word Problems
-> SOLUTION: Could someone help me out with these two;
Give the logarithms of the following;
log(base 10)3.20
log(base10)second root (its like the the cube root just a 2 on place of the 3) 6
Log On
Question 214156: Could someone help me out with these two;
Give the logarithms of the following;
log(base 10)3.20
log(base10)second root (its like the the cube root just a 2 on place of the 3) 6
would be cool if someone could explain to me how to work those to out! ;) Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! log(base 10)3.20
= 0.5051499... (by a calculator)
--------------------
log(base10)second root (its like the the cube root just a 2 on place of the 3) 6
=
= 0.3890756...
