SOLUTION: Some 5% alcohol Solution is mixed with another 20% alcohol solution to get a mixture of 25 liters of 14% solution. Find the amount of each alcohol solution before mixing.
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Question 214085: Some 5% alcohol Solution is mixed with another 20% alcohol solution to get a mixture of 25 liters of 14% solution. Find the amount of each alcohol solution before mixing. Found 2 solutions by nerdybill, josmiceli:Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! Some 5% alcohol Solution is mixed with another 20% alcohol solution to get a mixture of 25 liters of 14% solution. Find the amount of each alcohol solution before mixing.
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Let x = amount of 5% solution
then because the total mixture is 25 liters we have
25-x = amount of 20% solution
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Our equation:
.05x + .20(25-x) = .14(25)
.05x + 5 - .20x = 3.5
5 - .15x = 3.5
-.15x = -1.5
x = 10 liters (5% alcohol solution)
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20% alcohol solution:
25-x = 25-10 = 15 liters
You can put this solution on YOUR website! Let = liters of 5% solution
Let = liters of 20% solution
given:
(1)
Alcohol in 5% solution =
Alcohol in 20% solution =
-------------------------------------
(2)
Multiply both sides of (1) by and subtract from (2)
(2)
(1)
and, since
15 liters of 5% solution and 10 liters of 20% solution are needed
check:
OK
