SOLUTION: factor completely: 3x^2-13x+14

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Question 214081This question is from textbook Intermediate Algebra
: factor completely:
3x^2-13x+14
This question is from textbook Intermediate Algebra

Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
Factor completely:

3x%5E2-13x%2B14=%283x-7%29%28x-2%29

Step 1. We need to find two integers A and B that A*B=ac and A+B=b where

ax%5E2%2Bbx%2Bc in order to be factorable and a=3, b=-13 and c=14

Step 2. In the above example, then A*B=(3)(14)=42 and A+B=-13.

Step 3. After trial and error the numbers are A=-6 and B=-7

Step 4. Using step 3, we can use grouping as follows

3x%5E2-13x%2B14=3x%5E2-6x-7x%2B14 where -13x=-6x-7x

3x%5E2-13x%2B14=%283x%5E2-6x%29%2B%28-7x%2B14%29

Step 5. Factor out 3x in first group and -7 in second group

3x%5E2-13x%2B14=3x%28x-2%29%2B%28-7%29%28x-2%29

Step 6. Factor out (x-2) since it is common in both groups.

3x%5E2-13x%2B14=%283x-7%29%28x-2%29 ANSWER

We can use the FOIL method to verify

%283x-7%29%28x-2%29=3x%5E2-6x-7x%2B2%2A7=3x%5E2-13x%2B14

I hope the above steps were helpful.

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J