Question 214048:
Mae Jackson has a total of $6000 invested in two simple interest accounts. The annual simple interest
rate on one account is 9%. The annual simple interest rate on the second account is 6%. How much is
invested in each account if both accounts earn the same amount of interest?
Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! .09x=.06(6,000-x)
.09x=360-.06x
.15x-.06x=360
.15x=360
x=360/.15
x=2,400 invested @ 9%.
6,000-2,400=3,600 invested @ 6%.
Proof:
.09*2,400=.06*3,600
216=216
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