You can put this solution on YOUR website! (n-r)(nCr)=n(n-1Cr)
LHS=(n-r)(nCr)=(n-r)n!/{r!(n-r)!}=(n-r)n!/{r!(n-r)(n-r-1)!}=n!/{r!(n-r-1)!}
RHS=n(n-1Cr)=n(n-1)!/{r!(n-1-r)!}=n!/{r!(n-1-r)!}=lhs
note that we used n!=n(n-1)!here...since n!=n(n-1)(n-2)....3*2*1
=n(n-1)(n-2)....3*2*1=n[(n-1)(n-2)....3*2*1]=n(n-1)!