Question 213818: The first angle of a triangle is half the measure of the second angle. The measure of the third angle is 40 degress more than 4 times the measure of the first. Find the measure of each angle.
Found 2 solutions by stanbon, RAY100:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The first angle of a triangle is half the measure of the second angle. The measure of the third angle is 40 degress more than 4 times the measure of the first. Find the measure of each angle.
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Let the 2nd angle be "x".
Then the 1st angle is "2x"
And the 3rd angle is "4x+40"
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Equation:
x + 2x + 4x+40 = 180
7x = 140
x = 20 degrees (2nd angle)
2x = 40 degrees (1st angle)
4x+40 = 120 degrees (3rd angle)
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Cheers,
Stan H.
Answer by RAY100(1637) (Show Source):
You can put this solution on YOUR website! Let x,,y,,,z,,,be angles of triangle
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x = (1/2) y,,,,or y=2x,,,,,given
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z= 40 + 4z,,,,,,,,given
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but sum of angles = 180,,,or x + y + z = 180
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x + 2x + 40 +4x = 180
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7x = 140
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x= 20
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y=2x = 2*20 = 40
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z=40 +4x =40 + 4*20 =40 + 80 = 120
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checking,,,x+y+z=20+40+120 = 180,,,,,ok
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