SOLUTION: (2)Mrs.smith reading class can read a mean of 175 words per minute with a standared deviation of 20 words per minute. The top 3% of the class is to receive a special award. What is

Algebra ->  Probability-and-statistics -> SOLUTION: (2)Mrs.smith reading class can read a mean of 175 words per minute with a standared deviation of 20 words per minute. The top 3% of the class is to receive a special award. What is      Log On


   



Question 213797: (2)Mrs.smith reading class can read a mean of 175 words per minute with a standared deviation of 20 words per minute. The top 3% of the class is to receive a special award. What is the minimum number of words per minute a student would have to read in order to get the award?
Answer by stanbon(75887) About Me  (Show Source):
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Mrs.smith reading class can read a mean of 175 words per minute with a standared deviation of 20 words per minute. The top 3% of the class is to receive a special award. What is the minimum number of words per minute a student would have to read in order to get the award?
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Find the z-value separating the top 3% of a normal population from
the bottom 97%.
That value is z = 1.8808
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Find the associated raw score value using x = zs + u
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x = 1.8808*20 + 175
x = 212.62
Rounding up: 213 is the minimum number of words per minute.
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Cheers,
Stan H.