SOLUTION: A bus driver leaves the station at 10am at 40mph. He forgets to pack luggage underneath the bus and a car is dispatched 1hr later with the forgotten luggage. If the car has only 2h

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Question 213740: A bus driver leaves the station at 10am at 40mph. He forgets to pack luggage underneath the bus and a car is dispatched 1hr later with the forgotten luggage. If the car has only 2hrs to catch up the bus, how fast does the car need to drive?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
If the car drives 40 mi/hr or less, it can never
catch the bus.
The car leaves 1 hr after the bus has left
In 1 hr, the bus has gone
d+=40%2A1
d+=+40 mi
I have a stopwatch which I will start when the car leaves
and I'll stop it when the car catches the bus.
Both vehicles will drive for 2 hrs, but the bus has
a 40 mi headstart.
Let d = distance the car goes in 2 hrs
Let r = speed of the car in mi/hr
d+-+40 = distance the bus travels
Let t+=+2 hrs for both
For car:
(1) d+=+r%2A2
For bus:
(2) d+-+40+=+40%2A2
Substitute (1) in (2)
2r+-+40+=+80
2r+=+120
r+=+60
The car needs to go 60 mi/hr to catch the bus in 2 hrs
check answer
In 2 hrs, the bus goes
d+=+40%2A2
d+=+80+mi
80+%2B+40+=+120
The car needs to go a total of 120 mi in 2 hrs
d+=+r%2At
120+=+r%2A2
r+=+60 mi/hr
OK