SOLUTION: if 2t+(s-r)/3= t what is s in terms of r and t?

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Question 213485: if 2t+(s-r)/3= t what is s in terms of r and t?
Found 2 solutions by drj, Theo:
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
If 2t+(s-r)/3= t what is s in terms of r and t?

Step 1. Let's get rid of denominator by multiplying 3 to both sides of equation:

2t%2B%28s-r%29%2F3=+t

2%2A3%2At%2B%28s-r%29%2A3%2F3=+3%2At

6t%2B%28s-r%29=+3%2At

6t%2Bs-r=3t

Step 2. Add -6t+r to both sides of equation to get s.

6t%2Bs-r-6t%2Br=3t-6t%2Br

s=-3t%2Br ANSWER

Step 3. So s=-3t+r


I hope the above steps were helpful.

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Good luck in your studies!

Respectfully,
Dr J





Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
equation is 2t + (s-r)/3 = t
solve for s.
multiply both sides of the equation by 3 to get:
2*3*t + s - r = 3*t
add r and subtract 2*3*t from both sides of the equation to get:
s = 3*t - 2*3*t + r
this becomes:
s = 3t - 6t + r which becomes:
s = -3t + r
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if you let t = 1 and r = 1, you get s = -3 + 1 = -2
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if you substitute s = -2 and t = 1 and r = 1 into the original equation you get:
2t + (s-r)/3 = t becoming:
2 + (-2-1)/3 = 1 which becomes:
2 -(3/3) = 1 which becomes:
1 = 1 which is true so the value for s is good.
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your answer is:
s = -3t + r
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