SOLUTION: kx(squared)-6x+5=0. Find the values of k for which the roots are real numbers.

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Question 213450: kx(squared)-6x+5=0. Find the values of k for which the roots are real numbers.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
kx(squared)-6x+5=0. Find the values of k for which the roots are real numbers.
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Use the determinant:
b^2-4ac = 6^2-4k5
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To have Real Number Roots the determinant must be >= 0.
36-20k >= 0
Add 20k to both sides and read from right to left to get:
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20k <= 36
k <= 9/5
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Cheers,
Stan H.