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Question 21344: please help me solve this equation with my daughter. we have tried to solve -but cannot. -3x+2(4x-1)+6+6(-7x-15)+2(4x+6)-3(x+5)=4x+6x-3+4(-8x-5)-(-4x-5)-(-4x+6)+(2x-18)+6-3x+9x+8(4x+16)5x+1 That is called a killer equations that is what my teacher says.
Answer by venugopalramana(3286)   (Show Source):
You can put this solution on YOUR website! -3x+2(4x-1)+6+6(-7x-15)+2(4x+6)-3(x+5)=4x+6x-3+4(-8x-5)-(-4x-5)-(-4x+6)+(2x-18)+6-3x+9x+8(4x+16)5x+1...(I THINK YOU MISSED TO PUT +BEFORE 5X AT THE END...IT SHOULD BE +5X+1) That is called a killer equations that is what my teacher says.THERE IS NOTHING LIKE A KILLER IN MATHS.IT IS RECIPE FOR BETTER CONQUEST..IF YOU LEARN THE RIGHT WAY YOU WILL ITCH FOR MORE SUCH BATTLES!!!SO LET US LEARN NOW HOW TO COMBAT...
METHOD...
1.SIMPLIFY COMBINING LIKE TERMS ON L.H.S.AND R.H.S.SEPERATELY.
2.FOLLOW THE ORDER OF SIMPLIFICATION..BODMAS...BRACKET,OF,DIVISION,MULTIPLICATION,ADDITION AND SUBTRACTION IN THAT ORDER...
3.BE CAREFULL ON MINUS SIGN..IF IT IS BEFORE A BRACKET IT CHANGES THE SIGNS OF ALL TERMS WITHIN THE BRACKET....
4.BRING ALL UNKNOWNS TO ONE SIDE OF =...SAY L.H.S. AND KNOWNS TO THE OTHER SIDE R.H.S
5.SIMPLIFY AGAIN AS DESCRIBED ABOVE IF REQUIRED.
5.FINALLY YOU SHOULD HAVE ONE UNKNOWN ON L.H.S.AND ONE KNOWN ON R.H.S.
6.EVALUATE THE UNKNOWN..
SO LET US START NOW..........
-3x+2(4x-1)+6+6(-7x-15)+2(4x+6)-3(x+5)=4x+6x-3+4(-8x-5)-(-4x-5)-(-4x+6)+(2x-18)+6-3x+9x+8(4x+16)+5x+1
-3X+2*4X-2*1+6+6*(-7)X+6*(-15)+2*4X+2*6-3X-3*5=4X+6X-3+4*(-8)X+4*(-5)-(-4)X-(-5)-(-4)X-6+2X-18+6-3X+9X+8(4)X+8*16+5X+1
-3X+8X-2+6-42X-90+8X+12-3X-15=4X+6X-3-32X-20+4X+5+4X-6+2X-18+6-3X+9X+32X+128+5X+1
NOW WE CAN SIMPLIFY FUTHER BOTH SIDES SEPERATELY OR GO TO THE NEXT STEP OF BRINGING ALL UNKNOWNS TO L.H.S...AND KNOWNS TO R.H.S....NOTE THAT WHEN TRANSFERRING FROM L.H.S TO R.H.S AND VICEVERSA...+ BECOMES -.................. AND - BECOMES +...
WHILE TRANSFERRING, IT IS A GOOD PRACTICE TO START WITH L.H.S.STARTING FROM LEFT GOING IN AN ORDER TOWARDS RIGHT TILL YOU REACH THE = SIGN,WRITING ALL UNKNOWNS LEAVING OUT THE KNOWNS...NOW START FROM R.H.S.TRAVEL TOWARDS RIGHT PICKING ALL UNKNOWNS AND TRANSFERRING THEM TO L.H.S.(DONT FORGET TO CHNGE SIGN FROM + TO - AND - TO + AS MENTIONED ABOVE).AFTER FINISHING THIS NOW THERE ARE ONLY KNOWNS LEFT ON R.H.S.NOW TRANSFER THE KNOWNS ON L.H.S.TO R.H.S IN THE SAME MANNER..
-3X+8X-42X+8X-3X-4X-6X+32X-4X-4X-2X+3X-9X-32X-5X=-3-20+5-6-18+6+128+1+2-6+90-12+15
NOW ADD ALL + TERMS AND - TERMS SPERATELY AND COMBINE THEM AT THE END
-114X+51X=-65+247
-63X=182
NOW WE HAVE ONLY ONE TERM ON L.H.S. AND ONE TERM ON R.H.S.SO WE NOW TRANSFER THE COEFFICIENT OF X ON L.H.S. TO R.H.S...NOTE THAT IN SUCH A TRANSFER MULTIPLICATION BECOMES DIVISION AND DIVISION BECOMES MULTIPLICATION..
X= -182/63=-26/9
WELL ALL I CAN SAY IS THAT IT IS A LABORIOUS PROBLEM TESTING YOUR PATIENCE THAN PRESENTING ANY LEVEL OF DIFFICULTY
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