SOLUTION: A moving van leaves a house traveling at an average rate of 35mph. The family leaves the house in a car 3/4 hour later traveling the same route at an average rate of 50mph. How l
Question 213169This question is from textbook Prentice Hall Algebra I Louisiana
: A moving van leaves a house traveling at an average rate of 35mph. The family leaves the house in a car 3/4 hour later traveling the same route at an average rate of 50mph. How long will it take the family to catch up with the van? This question is from textbook Prentice Hall Algebra I Louisiana
You can put this solution on YOUR website! A moving van leaves a house traveling at an average rate of 35mph.
The family leaves the house in a car 3/4 hour later traveling the same route at an average rate of 50mph.
How long will it take the family to catch up with the van?
:
Change 3/4 hr to .75 hr
:
Let t = time required by the family to catch up
then
(t+.75) = Van travel time when it is caught
:
When this happens, they will have traveled the same distance
Write a distance equation: dis = speed * time
:
Car dist = Van dist
50t = 35(t+.75)
50t = 35t + 26.25
50t - 35t = 26.25
15t = 26.25
t =
t = 1.75 hrs for the family to catch the van
;
:
Check solution by ensuring that they traveled the same dist:
50 * 1.75 = 87.5 mi
35 * (1.75+.75) = 87.5
