SOLUTION: I;m not sure if you can help with this problem, but this is how the question was given to me..."hans and greta live 21 miles apart. at 1pm they start riding their bikes towards eac

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Question 212956: I;m not sure if you can help with this problem, but this is how the question was given to me..."hans and greta live 21 miles apart. at 1pm they start riding their bikes towards each other and meet at 1:45pm. if greta's average speed is 4 miles per hour faster than hans' average speed. find gretas average speed."
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
..."hans and greta live 21 miles apart. at 1pm they start riding their bikes towards each other and meet at 1:45pm. if greta's average speed is 4 miles per hour faster than hans' average speed. find gretas average speed."
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They travel 21 miles in 0.75 hours (45 minutes) so their combined speed is
28 mph. Their speeds are added going in opposite directions.
g + h = 28 (sum of speeds)
g = h + 4 (greta's speed is 4 more than that of hans)
Sub for g into the 1st eqn
(h+4) + h = 28
2h + 4 = 28
2h = 24
h = 12 mph
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g = 16 mph