SOLUTION: write an equation of the tangent function with period 3pi/8, phase shift -pi/5, and vertical shift -2 a)y=tan(8x/3 - 8pi/15)-2 b)y=tan(8x/3 + 8pi/15)-2 c)y=tan(16x/3 + 3pi/80)

Algebra ->  Trigonometry-basics -> SOLUTION: write an equation of the tangent function with period 3pi/8, phase shift -pi/5, and vertical shift -2 a)y=tan(8x/3 - 8pi/15)-2 b)y=tan(8x/3 + 8pi/15)-2 c)y=tan(16x/3 + 3pi/80)      Log On


   

Question 212802: write an equation of the tangent function with period 3pi/8, phase shift -pi/5, and vertical shift -2
a)y=tan(8x/3 - 8pi/15)-2
b)y=tan(8x/3 + 8pi/15)-2
c)y=tan(16x/3 + 3pi/80)-2
d)y=tan(8x/3 - 3pi/40)-2
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
Using a general form of y+=+tan%28B%28x-D%29%29+%2B+C where B = (the natural period of tan)/(period of this function), D is the phase shift and C is the vertical shift, we want an equation where B+=+%28pi%29%2F%28%283%2Api%29%2F8%29+=+8%2F3, D+=+-%28pi%2F5%29 and C = -2. We want an equation that looks like:
y+=+tan%28%288%2F3%29%28x+-+%28-%28pi%2F5%29%29%29%29+%2B+%28-2%29
or
y+=+tan%28%288%2F3%29%28x+%2B+pi%2F5%29%29+-+2
None of the answers look this this. But if we multiply out the argument of tan we get:
y+=+tan%28%288%2F3%29x+%2B+%288%2Api%29%2F15%29+-+2
which matches answer "b"