Question 212564: x+y-2z=5
x+2y+z=8
2x+3y-z=1
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! x+y-2z=5
x+2y+z=8
2x+3y-z=1
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subtract the 1st Eq. from the 2nd
Subtract twice the 1st Eq. from the 3rd
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x+y-2z=5
0+y+3z=3
0+y+3z=-10
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Subtract the 2nd Eq. from the 3rd:
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x+y-2z=5
0+y+3z=3
0+0+0 =7
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The last equation shows a contradiction.
There is no solution for the system.
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Cheers,
Stan H.
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