SOLUTION: need help with finding the equation of the line wich contains the point (0,1) and has the slope 1 ?

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Question 212517: need help with finding the equation of the line wich contains the point (0,1) and has the slope 1 ?

Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
Need help with finding the equation of the line which contains the point (0,1) and has the slope 1 ?

Step 1. The slope m is given as

m=%28y2-y1%29%2F%28x2-x1%29

Step 2. Let (x1,y1)=(0,1) or x1=0 and y1=1 . Let other point be ((x2,y2)=(x,y) or x2=x and y2=y.

Step 3. Now we're given m=1. Substituting above values and variables in the slope equation m yields the following steps:

m=%28y2-y1%29%2F%28x2-x1%29

1=%28y-1%29%2F%28x-0%29

Step 4. Multiply x to both sides to get rid of denominator on right side of equation.

x=y-1

Step 5. Now add 1 to both side of equation.

x%2B1=y

Note: the above equation can be rewritten as
x-y=-1
And the graph is shown below which is consistent with the above steps.

Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation 1+x+%2B+-1+y+=+-1 describes a sloping line. For any
equation ax+by+c = 0, slope is -a%2Fb+=+-1%2F-1.
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. -1/1 = -1.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is -1/-1 = 1.
  • Slope is -1/-1 = 1.
  • Equation in slope-intercept form: y=1*x+1.
graph%28+500%2C+500%2C+-1-8%2C+-1%2B8%2C+1-8%2C+1%2B8%2C+1%2Ax%2B1+%29+




I hope the above steps were helpful. Good luck in your studies!

Respectfully,
Dr J

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