Question 212481: x^2-8x>0
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! x^2-8x>0
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x(x-8) > 0
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Draw a number line.
Plot x = 0 and x = 8
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Check a value in each of the intervals to see where solutions lie.
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If x = -10 you get -*- > 0 ; true so solutions in (-inf,0)
If x = 5 you get +*- > 0 ; false
If x = 10 you get +*+ > 0 ; true so solutions in (8,+inf)
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Cheers,
Stan H.
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