SOLUTION: I need help solving these two equations. I have tried over and over and am missing a step somewhere: x-5 over x+4 = x-1 over x+3 Solve for x 7 over x-2 + 2 over x+2 = -4x ove

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I need help solving these two equations. I have tried over and over and am missing a step somewhere: x-5 over x+4 = x-1 over x+3 Solve for x 7 over x-2 + 2 over x+2 = -4x ove      Log On


   



Question 212427: I need help solving these two equations. I have tried over and over and am missing a step somewhere:
x-5 over x+4 = x-1 over x+3 Solve for x
7 over x-2 + 2 over x+2 = -4x over x^2-4 solve for x
Thank you very much.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
x-5 over x+4 = x-1 over x+3 Solve for x
Cross multiply
(x-5)*(x+3) = (x+4)*(x-1)
x%5E2+-+2x+-+15+=+x%5E2+%2B+3x+-+4
-2x-15 = 3x-4
5x = -11
x = -11/5
-----------------
7 over x-2 + 2 over x+2 = -4x over x^2-4 solve for x
7%2F%28x-2%29+%2B+2%2F%28x%2B2%29+=+-4x%2F%28x%5E2-4%29
(x^2-4) = ((x-2)*(x+2) and is the common denominator
Multiply thru by (x^2-4)
7(x+2) + 2(x-2) = -4x
7x+14 + 2x-4 = -4x
9x + 10 = -4x
13x = -10
x = -10/13