SOLUTION: "The distance that a freely falling body falls varies directly as the square of the time it falls. If a body falls 400 feet in 5 seconds, how far does it fall in 3 seconds?"
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Question 212411This question is from textbook Intermediate Algebra
: "The distance that a freely falling body falls varies directly as the square of the time it falls. If a body falls 400 feet in 5 seconds, how far does it fall in 3 seconds?"
I respectfully request if you can show all work. Thank you very much. This question is from textbook Intermediate Algebra
You can put this solution on YOUR website! "The distance that a freely falling body falls varies directly as the square of the time it falls. If a body falls 400 feet in 5 seconds, how far does it fall in 3 seconds?"
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d = kt^2
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Solve for "k"
400 = k(5)^2
k = 400/25 = 16
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Equation:
d = 16t^2
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how far does it fall in 3 seconds?"
d = 16*(3^2)
d = 144 feet
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Cheers,
Stan H.
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